12x^2-17x-18=0

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Solution for 12x^2-17x-18=0 equation:



12x^2-17x-18=0
a = 12; b = -17; c = -18;
Δ = b2-4ac
Δ = -172-4·12·(-18)
Δ = 1153
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-17)-\sqrt{1153}}{2*12}=\frac{17-\sqrt{1153}}{24} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-17)+\sqrt{1153}}{2*12}=\frac{17+\sqrt{1153}}{24} $

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